Base | Representation |
---|---|
bin | 10000110001000110100… |
… | …000000001010100000011 |
3 | 11002011010011121122110201 |
4 | 100301012200001110003 |
5 | 122334233403100220 |
6 | 2241155022110031 |
7 | 146150301460141 |
oct | 20610640012403 |
9 | 4064104548421 |
10 | 1152234034435 |
11 | 40472908a1a0 |
12 | 167388a1b317 |
13 | 84869634a63 |
14 | 3daa87b4591 |
15 | 1ee8b536d0a |
hex | 10c46801503 |
1152234034435 has 16 divisors (see below), whose sum is σ = 1513824531552. Its totient is φ = 834963148800.
The previous prime is 1152234034429. The next prime is 1152234034463. The reversal of 1152234034435 is 5344304322511.
It is not a de Polignac number, because 1152234034435 - 25 = 1152234034403 is a prime.
It is a super-2 number, since 2×11522340344352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1152234034394 and 1152234034403.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37800126 + ... + 37830595.
It is an arithmetic number, because the mean of its divisors is an integer number (94614033222).
Almost surely, 21152234034435 is an apocalyptic number.
1152234034435 is a deficient number, since it is larger than the sum of its proper divisors (361590497117).
1152234034435 is a wasteful number, since it uses less digits than its factorization.
1152234034435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75631014.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 1152234034435 its reverse (5344304322511), we get a palindrome (6496538356946).
The spelling of 1152234034435 in words is "one trillion, one hundred fifty-two billion, two hundred thirty-four million, thirty-four thousand, four hundred thirty-five".
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