Base | Representation |
---|---|
bin | 11010001100110110101010… |
… | …000100111010111100111110 |
3 | 120010000010022012202200021010 |
4 | 122030312222010322330332 |
5 | 110100432210414014100 |
6 | 1045025032142420050 |
7 | 33162163353261663 |
oct | 3214665204727476 |
9 | 503003265680233 |
10 | 115232531001150 |
11 | 3379792970a572 |
12 | 10b10a05591626 |
13 | 4c3b4c52119a4 |
14 | 20653da013a6a |
15 | d4c6e12d3750 |
hex | 68cdaa13af3e |
115232531001150 has 48 divisors (see below), whose sum is σ = 285780071404800. Its totient is φ = 30728309931360.
The previous prime is 115232531001143. The next prime is 115232531001209. The reversal of 115232531001150 is 51100135232511.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8226811 + ... + 17266889.
It is an arithmetic number, because the mean of its divisors is an integer number (5953751487600).
Almost surely, 2115232531001150 is an apocalyptic number.
115232531001150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
115232531001150 is an abundant number, since it is smaller than the sum of its proper divisors (170547540403650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115232531001150 is a wasteful number, since it uses less digits than its factorization.
115232531001150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9125073 (or 9125068 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 30.
Adding to 115232531001150 its reverse (51100135232511), we get a palindrome (166332666233661).
The spelling of 115232531001150 in words is "one hundred fifteen trillion, two hundred thirty-two billion, five hundred thirty-one million, one thousand, one hundred fifty".
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