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115324303142 = 257662151571
BaseRepresentation
bin110101101100111011…
…1010011011100100110
3102000200011000121012202
41223121313103130212
53342141010200032
6124551304014502
711221562255066
oct1533167233446
9360604017182
10115324303142
11449aa620944
121a425a61432
13ab4b5b5539
1458203833a6
152eee75dd62

115324303142 has 4 divisors (see below), whose sum is σ = 172986454716. Its totient is φ = 57662151570.

The previous prime is 115324303139. The next prime is 115324303147. The reversal of 115324303142 is 241303423511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241303423511 = 453961531551.

It is a super-2 number, since 2×1153243031422 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115324303147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28831075784 + ... + 28831075787.

It is an arithmetic number, because the mean of its divisors is an integer number (43246613679).

Almost surely, 2115324303142 is an apocalyptic number.

115324303142 is a deficient number, since it is larger than the sum of its proper divisors (57662151574).

115324303142 is an equidigital number, since it uses as much as digits as its factorization.

115324303142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57662151573.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 115324303142 its reverse (241303423511), we get a palindrome (356627726653).

The spelling of 115324303142 in words is "one hundred fifteen billion, three hundred twenty-four million, three hundred three thousand, one hundred forty-two".

Divisors: 1 2 57662151571 115324303142