Base | Representation |
---|---|
bin | 110101101100111011… |
… | …1010011011100100110 |
3 | 102000200011000121012202 |
4 | 1223121313103130212 |
5 | 3342141010200032 |
6 | 124551304014502 |
7 | 11221562255066 |
oct | 1533167233446 |
9 | 360604017182 |
10 | 115324303142 |
11 | 449aa620944 |
12 | 1a425a61432 |
13 | ab4b5b5539 |
14 | 58203833a6 |
15 | 2eee75dd62 |
hex | 1ad9dd3726 |
115324303142 has 4 divisors (see below), whose sum is σ = 172986454716. Its totient is φ = 57662151570.
The previous prime is 115324303139. The next prime is 115324303147. The reversal of 115324303142 is 241303423511.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241303423511 = 453961 ⋅531551.
It is a super-2 number, since 2×1153243031422 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115324303147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28831075784 + ... + 28831075787.
It is an arithmetic number, because the mean of its divisors is an integer number (43246613679).
Almost surely, 2115324303142 is an apocalyptic number.
115324303142 is a deficient number, since it is larger than the sum of its proper divisors (57662151574).
115324303142 is an equidigital number, since it uses as much as digits as its factorization.
115324303142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57662151573.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 115324303142 its reverse (241303423511), we get a palindrome (356627726653).
The spelling of 115324303142 in words is "one hundred fifteen billion, three hundred twenty-four million, three hundred three thousand, one hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.119 sec. • engine limits •