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115324303151 = 2320693242309
BaseRepresentation
bin110101101100111011…
…1010011011100101111
3102000200011000121020002
41223121313103130233
53342141010200101
6124551304014515
711221562255111
oct1533167233457
9360604017202
10115324303151
11449aa620952
121a425a6143b
13ab4b5b5545
1458203833b1
152eee75dd6b
hex1ad9dd372f

115324303151 has 8 divisors (see below), whose sum is σ = 120344715360. Its totient is φ = 110304416992.

The previous prime is 115324303147. The next prime is 115324303181. The reversal of 115324303151 is 151303423511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115324303151 - 22 = 115324303147 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115324303111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 354785 + ... + 597093.

It is an arithmetic number, because the mean of its divisors is an integer number (15043089420).

Almost surely, 2115324303151 is an apocalyptic number.

115324303151 is a deficient number, since it is larger than the sum of its proper divisors (5020412209).

115324303151 is a wasteful number, since it uses less digits than its factorization.

115324303151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 263025.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 115324303151 its reverse (151303423511), we get a palindrome (266627726662).

The spelling of 115324303151 in words is "one hundred fifteen billion, three hundred twenty-four million, three hundred three thousand, one hundred fifty-one".

Divisors: 1 23 20693 242309 475939 5573107 5014100137 115324303151