Base | Representation |
---|---|
bin | 10101101000001001… |
… | …01010110011111011 |
3 | 1002222012020211102002 |
4 | 22310010222303323 |
5 | 142234412314103 |
6 | 5200053131215 |
7 | 560506234211 |
oct | 126404526373 |
9 | 32865224362 |
10 | 11611057403 |
11 | 4a19159310 |
12 | 2300629b0b |
13 | 11306c518a |
14 | 7c20d4cb1 |
15 | 47e543488 |
hex | 2b412acfb |
11611057403 has 8 divisors (see below), whose sum is σ = 12744319296. Its totient is φ = 10490747400.
The previous prime is 11611057399. The next prime is 11611057411. The reversal of 11611057403 is 30475011611.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11611057403 - 22 = 11611057399 is a prime.
It is a super-2 number, since 2×116110574032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11611057463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3236093 + ... + 3239678.
It is an arithmetic number, because the mean of its divisors is an integer number (1593039912).
Almost surely, 211611057403 is an apocalyptic number.
11611057403 is a deficient number, since it is larger than the sum of its proper divisors (1133261893).
11611057403 is a wasteful number, since it uses less digits than its factorization.
11611057403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6475945.
The product of its (nonzero) digits is 2520, while the sum is 29.
The spelling of 11611057403 in words is "eleven billion, six hundred eleven million, fifty-seven thousand, four hundred three".
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