Base | Representation |
---|---|
bin | 1010100110100000011011… |
… | …0110011001111000010111 |
3 | 1112021100212102002012012211 |
4 | 2221220012312121320113 |
5 | 3011440312434311143 |
6 | 40442554404054251 |
7 | 2312110543411162 |
oct | 251500666317027 |
9 | 45240772065184 |
10 | 11656656166423 |
11 | 3794618576944 |
12 | 138317a694387 |
13 | 6672aab1c998 |
14 | 2c4284162ad9 |
15 | 15333a41949d |
hex | a9a06d99e17 |
11656656166423 has 2 divisors, whose sum is σ = 11656656166424. Its totient is φ = 11656656166422.
The previous prime is 11656656166417. The next prime is 11656656166439. The reversal of 11656656166423 is 32466165665611.
11656656166423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11656656166423 - 241 = 9457632910871 is a prime.
It is a super-2 number, since 2×116566561664232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11656656166123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5828328083211 + 5828328083212.
It is an arithmetic number, because the mean of its divisors is an integer number (5828328083212).
Almost surely, 211656656166423 is an apocalyptic number.
11656656166423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11656656166423 is an equidigital number, since it uses as much as digits as its factorization.
11656656166423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27993600, while the sum is 58.
The spelling of 11656656166423 in words is "eleven trillion, six hundred fifty-six billion, six hundred fifty-six million, one hundred sixty-six thousand, four hundred twenty-three".
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