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BaseRepresentation
bin1010101101100000111111…
…0101100001000100011001
31112200212122222110011110101
42223120033311201010121
53020423412344403303
641014150501015401
72323602450255343
oct253301765410431
945625588404411
1011777066012953
1138306978117aa
1213a25836b4561
13675759bb5397
142ca027ab4293
1515653637ad1d
hexab60fd61119

11777066012953 has 4 divisors (see below), whose sum is σ = 11781054185908. Its totient is φ = 11773077840000.

The previous prime is 11777066012939. The next prime is 11777066013001. The reversal of 11777066012953 is 35921066077711.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6751542247129 + 5025523765824 = 2598373^2 + 2241768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11777066012953 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11777066012894 and 11777066012903.

It is not an unprimeable number, because it can be changed into a prime (11777066016953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1994082048 + ... + 1994087953.

It is an arithmetic number, because the mean of its divisors is an integer number (2945263546477).

Almost surely, 211777066012953 is an apocalyptic number.

It is an amenable number.

11777066012953 is a deficient number, since it is larger than the sum of its proper divisors (3988172955).

11777066012953 is an equidigital number, since it uses as much as digits as its factorization.

11777066012953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3988172954.

The product of its (nonzero) digits is 3333960, while the sum is 55.

The spelling of 11777066012953 in words is "eleven trillion, seven hundred seventy-seven billion, sixty-six million, twelve thousand, nine hundred fifty-three".

Divisors: 1 2953 3988170001 11777066012953