Base | Representation |
---|---|
bin | 1010110001101100011010… |
… | …1011100111000001000111 |
3 | 1112221201221221120012122021 |
4 | 2230123012223213001013 |
5 | 3023112422344420033 |
6 | 41111142111544011 |
7 | 2332023424525651 |
oct | 254330653470107 |
9 | 45851857505567 |
10 | 11848853123143 |
11 | 3859085764143 |
12 | 13b4478b2b007 |
13 | 67c45a658a8a |
14 | 2cd6b7ba96d1 |
15 | 1583387eab2d |
hex | ac6c6ae7047 |
11848853123143 has 2 divisors, whose sum is σ = 11848853123144. Its totient is φ = 11848853123142.
The previous prime is 11848853123053. The next prime is 11848853123171. The reversal of 11848853123143 is 34132135884811.
11848853123143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11848853123143 - 217 = 11848852992071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11848853123243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5924426561571 + 5924426561572.
It is an arithmetic number, because the mean of its divisors is an integer number (5924426561572).
Almost surely, 211848853123143 is an apocalyptic number.
11848853123143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11848853123143 is an equidigital number, since it uses as much as digits as its factorization.
11848853123143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2211840, while the sum is 52.
The spelling of 11848853123143 in words is "eleven trillion, eight hundred forty-eight billion, eight hundred fifty-three million, one hundred twenty-three thousand, one hundred forty-three".
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