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11983412708117 is a prime number
BaseRepresentation
bin1010111001100001101100…
…0011101100001100010101
31120102121021122011100222122
42232120123003230030111
53032314012123124432
641253034230505325
72344526065241654
oct256303303541425
946377248140878
1011983412708117
113900156080a14
121416570805245
1368c05306a186
142d6000a5119b
1515bab1abc612
hexae61b0ec315

11983412708117 has 2 divisors, whose sum is σ = 11983412708118. Its totient is φ = 11983412708116.

The previous prime is 11983412708107. The next prime is 11983412708177. The reversal of 11983412708117 is 71180721438911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7959400780081 + 4024011928036 = 2821241^2 + 2005994^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11983412708117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11983412708107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991706354058 + 5991706354059.

It is an arithmetic number, because the mean of its divisors is an integer number (5991706354059).

Almost surely, 211983412708117 is an apocalyptic number.

It is an amenable number.

11983412708117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11983412708117 is an equidigital number, since it uses as much as digits as its factorization.

11983412708117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 677376, while the sum is 53.

The spelling of 11983412708117 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, seven hundred eight thousand, one hundred seventeen".