Base | Representation |
---|---|
bin | 1010111001100001101100… |
… | …0011101100001101011111 |
3 | 1120102121021122011101002101 |
4 | 2232120123003230031133 |
5 | 3032314012123130231 |
6 | 41253034230505531 |
7 | 2344526065242121 |
oct | 256303303541537 |
9 | 46377248141071 |
10 | 11983412708191 |
11 | 3900156080a81 |
12 | 14165708052a7 |
13 | 68c05306a212 |
14 | 2d6000a51211 |
15 | 15bab1abc661 |
hex | ae61b0ec35f |
11983412708191 has 2 divisors, whose sum is σ = 11983412708192. Its totient is φ = 11983412708190.
The previous prime is 11983412708177. The next prime is 11983412708213. The reversal of 11983412708191 is 19180721438911.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11983412708191 - 219 = 11983412183903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11983412706191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991706354095 + 5991706354096.
It is an arithmetic number, because the mean of its divisors is an integer number (5991706354096).
Almost surely, 211983412708191 is an apocalyptic number.
11983412708191 is a deficient number, since it is larger than the sum of its proper divisors (1).
11983412708191 is an equidigital number, since it uses as much as digits as its factorization.
11983412708191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 55.
The spelling of 11983412708191 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, seven hundred eight thousand, one hundred ninety-one".
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