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BaseRepresentation
bin1010111001100001101100…
…0011101100001101011111
31120102121021122011101002101
42232120123003230031133
53032314012123130231
641253034230505531
72344526065242121
oct256303303541537
946377248141071
1011983412708191
113900156080a81
1214165708052a7
1368c05306a212
142d6000a51211
1515bab1abc661
hexae61b0ec35f

11983412708191 has 2 divisors, whose sum is σ = 11983412708192. Its totient is φ = 11983412708190.

The previous prime is 11983412708177. The next prime is 11983412708213. The reversal of 11983412708191 is 19180721438911.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11983412708191 - 219 = 11983412183903 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11983412706191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991706354095 + 5991706354096.

It is an arithmetic number, because the mean of its divisors is an integer number (5991706354096).

Almost surely, 211983412708191 is an apocalyptic number.

11983412708191 is a deficient number, since it is larger than the sum of its proper divisors (1).

11983412708191 is an equidigital number, since it uses as much as digits as its factorization.

11983412708191 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 870912, while the sum is 55.

The spelling of 11983412708191 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, seven hundred eight thousand, one hundred ninety-one".