119981791104403 has 2 divisors, whose sum is σ = 119981791104404. Its totient is φ = 119981791104402.

The previous prime is 119981791104389. The next prime is 119981791104431. The reversal of 119981791104403 is 304401197189911.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-119981791104403 is a prime.

It is not a weakly prime, because it can be changed into another prime (119981791104443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59990895552201 + 59990895552202.

It is an arithmetic number, because the mean of its divisors is an integer number (59990895552202).

Almost surely, 2^{119981791104403} is an apocalyptic number.

119981791104403 is a deficient number, since it is larger than the sum of its proper divisors (1).

119981791104403 is an equidigital number, since it uses as much as digits as its factorization.

119981791104403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1959552, while the sum is 58.

The spelling of 119981791104403 in words is "one hundred nineteen trillion, nine hundred eighty-one billion, seven hundred ninety-one million, one hundred four thousand, four hundred three".