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119993 is a prime number
BaseRepresentation
bin11101010010111001
320002121012
4131102321
512314433
62323305
71006556
oct352271
9202535
10119993
1182175
1259535
1342803
1431a2d
1525848
hex1d4b9

119993 has 2 divisors, whose sum is σ = 119994. Its totient is φ = 119992.

The previous prime is 119983. The next prime is 120011. The reversal of 119993 is 399911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76729 + 43264 = 277^2 + 208^2 .

It is an emirp because it is prime and its reverse (399911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119993 - 26 = 119929 is a prime.

It is not a weakly prime, because it can be changed into another prime (119923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59996 + 59997.

It is an arithmetic number, because the mean of its divisors is an integer number (59997).

2119993 is an apocalyptic number.

It is an amenable number.

119993 is a deficient number, since it is larger than the sum of its proper divisors (1).

119993 is an equidigital number, since it uses as much as digits as its factorization.

119993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2187, while the sum is 32.

The square root of 119993 is about 346.4000577367. The cubic root of 119993 is about 49.3232823855.

The spelling of 119993 in words is "one hundred nineteen thousand, nine hundred ninety-three".