12000123300013 has 4 divisors (see below), whose sum is σ = 12000255059520. Its totient is φ = 11999991540508.

The previous prime is 12000123299999. The next prime is 12000123300019. The reversal of 12000123300013 is 31000332100021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12000123300013 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12000123300013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000123300019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65743045 + ... + 65925322.

It is an arithmetic number, because the mean of its divisors is an integer number (3000063764880).

Almost surely, 2^{12000123300013} is an apocalyptic number.

It is an amenable number.

12000123300013 is a deficient number, since it is larger than the sum of its proper divisors (131759507).

12000123300013 is an equidigital number, since it uses as much as digits as its factorization.

12000123300013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131759506.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 12000123300013 its reverse (31000332100021), we get a palindrome (43000455400034).

The spelling of 12000123300013 in words is "twelve trillion, one hundred twenty-three million, three hundred thousand, thirteen".