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12000230300413 is a prime number
BaseRepresentation
bin1010111010100000010101…
…1101101101101011111101
31120111012200200102120120101
42232220011131231223331
53033102432424103123
641304455114121101
72345662615356205
oct256500535555375
946435620376511
1012000230300413
1139072a6182a23
121419884a20191
13690803325814
142d6b5840b405
1515c248262aad
hexaea0576dafd

12000230300413 has 2 divisors, whose sum is σ = 12000230300414. Its totient is φ = 12000230300412.

The previous prime is 12000230300249. The next prime is 12000230300441. The reversal of 12000230300413 is 31400303200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9366403169764 + 2633827130649 = 3060458^2 + 1622907^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12000230300413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000230300483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000115150206 + 6000115150207.

It is an arithmetic number, because the mean of its divisors is an integer number (6000115150207).

Almost surely, 212000230300413 is an apocalyptic number.

It is an amenable number.

12000230300413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000230300413 is an equidigital number, since it uses as much as digits as its factorization.

12000230300413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12000230300413 its reverse (31400303200021), we get a palindrome (43400533500434).

The spelling of 12000230300413 in words is "twelve trillion, two hundred thirty million, three hundred thousand, four hundred thirteen".