Search a number
-
+
12001110330133 = 88093136232281
BaseRepresentation
bin1010111010100011100111…
…1010110000101100010101
31120111021222000100201101201
42232220321322300230111
53033111233221031013
641305122312152501
72346023462451421
oct256507172605425
946437860321351
1012001110330133
113907707a05311
121419a8b698731
13690913749472
142d6bdd249b81
1515c29a6473dd
hexaea39eb0b15

12001110330133 has 4 divisors (see below), whose sum is σ = 12001246650508. Its totient is φ = 12000974009760.

The previous prime is 12001110330113. The next prime is 12001110330151. The reversal of 12001110330133 is 33103301110021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3196021458564 + 8805088871569 = 1787742^2 + 2967337^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12001110330133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12001110330133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12001110330113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68028048 + ... + 68204233.

It is an arithmetic number, because the mean of its divisors is an integer number (3000311662627).

Almost surely, 212001110330133 is an apocalyptic number.

It is an amenable number.

12001110330133 is a deficient number, since it is larger than the sum of its proper divisors (136320375).

12001110330133 is an equidigital number, since it uses as much as digits as its factorization.

12001110330133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 136320374.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 12001110330133 its reverse (33103301110021), we get a palindrome (45104411440154).

The spelling of 12001110330133 in words is "twelve trillion, one billion, one hundred ten million, three hundred thirty thousand, one hundred thirty-three".

Divisors: 1 88093 136232281 12001110330133