Base | Representation |
---|---|
bin | 1010111011001001001110… |
… | …0000000111100110010111 |
3 | 1120112021000101221011022201 |
4 | 2232302103200013212113 |
5 | 3033242421011330403 |
6 | 41313512014105331 |
7 | 2346531545624650 |
oct | 256622340074627 |
9 | 46467011834281 |
10 | 12011203230103 |
11 | 3910a17101460 |
12 | 141ba277ab247 |
13 | 69186176281c |
14 | 2d74b9872527 |
15 | 15c68b75621d |
hex | aec93807997 |
12011203230103 has 16 divisors (see below), whose sum is σ = 15458071357440. Its totient is φ = 9057463682400.
The previous prime is 12011203230053. The next prime is 12011203230113. The reversal of 12011203230103 is 30103230211021.
12011203230103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12011203230103 - 221 = 12011201132951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12011203230113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2515959748 + ... + 2515964521.
It is an arithmetic number, because the mean of its divisors is an integer number (966129459840).
Almost surely, 212011203230103 is an apocalyptic number.
12011203230103 is a deficient number, since it is larger than the sum of its proper divisors (3446868127337).
12011203230103 is a wasteful number, since it uses less digits than its factorization.
12011203230103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5031924318.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12011203230103 its reverse (30103230211021), we get a palindrome (42114433441124).
The spelling of 12011203230103 in words is "twelve trillion, eleven billion, two hundred three million, two hundred thirty thousand, one hundred three".
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