| Base | Representation |
|---|---|
| bin | 1010111011001100001011… |
| … | …1111100011100000000000 |
| 3 | 1120112100001221012021010220 |
| 4 | 2232303002333203200000 |
| 5 | 3033301034000000000 |
| 6 | 41314123035423040 |
| 7 | 2346560362226160 |
| oct | 256630277434000 |
| 9 | 46470057167126 |
| 10 | 12012000000000 |
| 11 | 3911295936480 |
| 12 | 142000a5b4a80 |
| 13 | 69195a8543c0 |
| 14 | 2d75535da5a0 |
| 15 | 15c6d66911a0 |
| hex | aecc2fe3800 |
12012000000000 has 1920 divisors, whose sum is σ = 53746869496320. Its totient is φ = 2304000000000.
The previous prime is 12011999999999. The next prime is 12012000000031. The reversal of 12012000000000 is 21021.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (1920).
It is a Harshad number since it is a multiple of its sum of digits (6).
It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 923999999994 + ... + 924000000006.
It is an arithmetic number, because the mean of its divisors is an integer number (27993161196).
Almost surely, 212012000000000 is an apocalyptic number.
12012000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12012000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26873434748160).
12012000000000 is an abundant number, since it is smaller than the sum of its proper divisors (41734869496320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012000000000 is an frugal number, since it uses more digits than its factorization.
12012000000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101 (or 41 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 6.
Adding to 12012000000000 its reverse (21021), we get a palindrome (12012000021021).
It can be divided in two parts, 120 and 12000000000, that multiplied together give a square (1440000000000 = 12000002).
The spelling of 12012000000000 in words is "twelve trillion, twelve billion", and thus it is an aban number and an uban number.
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