1201333331003 has 4 divisors (see below), whose sum is σ = 1293743587248. Its totient is φ = 1108923074760.

The previous prime is 1201333330871. The next prime is 1201333331017. The reversal of 1201333331003 is 3001333331021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201333331003 - 2¹⁰ = 1201333329979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1201333331003.

It is not an unprimeable number, because it can be changed into a prime (1201333331603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46205128103 + ... + 46205128128.

It is an arithmetic number, because the mean of its divisors is an integer number (323435896812).

Almost surely, 2^{1201333331003} is an apocalyptic number.

1201333331003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1201333331003 is a deficient number, since it is larger than the sum of its proper divisors (92410256245).

1201333331003 is an equidigital number, since it uses as much as digits as its factorization.

1201333331003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92410256244.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 1201333331003 its reverse (3001333331021), we get a palindrome (4202666662024).

The spelling of 1201333331003 in words is "one trillion, two hundred one billion, three hundred thirty-three million, three hundred thirty-one thousand, three".