Base | Representation |
---|---|
bin | 101101110101… |
… | …001000100011 |
3 | 211121101021020 |
4 | 231311020203 |
5 | 11033422430 |
6 | 1105300523 |
7 | 204055401 |
oct | 55651043 |
9 | 24541236 |
10 | 12014115 |
11 | 6866423 |
12 | 4034743 |
13 | 2648559 |
14 | 184a471 |
15 | 10c4b10 |
hex | b75223 |
12014115 has 16 divisors (see below), whose sum is σ = 19305216. Its totient is φ = 6380000.
The previous prime is 12014063. The next prime is 12014117. The reversal of 12014115 is 51141021.
It is a happy number.
12014115 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12014115 - 210 = 12013091 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a junction number, because it is equal to n+sod(n) for n = 12014094 and 12014103.
It is not an unprimeable number, because it can be changed into a prime (12014117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2170 + ... + 5360.
It is an arithmetic number, because the mean of its divisors is an integer number (1206576).
Almost surely, 212014115 is an apocalyptic number.
12014115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12014115 is a deficient number, since it is larger than the sum of its proper divisors (7291101).
12014115 is a wasteful number, since it uses less digits than its factorization.
12014115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3450.
The product of its (nonzero) digits is 40, while the sum is 15.
The square root of 12014115 is about 3466.1383411514. The cubic root of 12014115 is about 229.0325780136.
Adding to 12014115 its reverse (51141021), we get a palindrome (63155136).
The spelling of 12014115 in words is "twelve million, fourteen thousand, one hundred fifteen".
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