12014312012141 has 4 divisors (see below), whose sum is σ = 12014417211900. Its totient is φ = 12014206812384.

The previous prime is 12014312012077. The next prime is 12014312012167. The reversal of 12014312012141 is 14121021341021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6544279796041 + 5470032216100 = 2558179^2 + 2338810^2 .

It is a cyclic number.

It is not a de Polignac number, because 12014312012141 - 2⁶ = 12014312012077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12014312012191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52428386 + ... + 52657043.

It is an arithmetic number, because the mean of its divisors is an integer number (3003604302975).

Almost surely, 2^{12014312012141} is an apocalyptic number.

It is an amenable number.

12014312012141 is a deficient number, since it is larger than the sum of its proper divisors (105199759).

12014312012141 is a wasteful number, since it uses less digits than its factorization.

12014312012141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105199758.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 12014312012141 its reverse (14121021341021), we get a palindrome (26135333353162).

The spelling of 12014312012141 in words is "twelve trillion, fourteen billion, three hundred twelve million, twelve thousand, one hundred forty-one".