Base | Representation |
---|---|
bin | 1010111011011000111100… |
… | …1001000011101010111101 |
3 | 1120112122220122000111001021 |
4 | 2232312033021003222331 |
5 | 3033330042302340013 |
6 | 41315450550144141 |
7 | 2350041301505521 |
oct | 256661711035275 |
9 | 46478818014037 |
10 | 12015425043133 |
11 | 3912793217036 |
12 | 1420805652051 |
13 | 692085307c45 |
14 | 2d779a445d81 |
15 | 15c8371e3a8d |
hex | aed8f243abd |
12015425043133 has 4 divisors (see below), whose sum is σ = 12031596544608. Its totient is φ = 11999253541660.
The previous prime is 12015425043091. The next prime is 12015425043163. The reversal of 12015425043133 is 33134052451021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12015425043133 - 213 = 12015425034941 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12015425043163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8085749623 + ... + 8085751108.
It is an arithmetic number, because the mean of its divisors is an integer number (3007899136152).
Almost surely, 212015425043133 is an apocalyptic number.
It is an amenable number.
12015425043133 is a deficient number, since it is larger than the sum of its proper divisors (16171501475).
12015425043133 is an equidigital number, since it uses as much as digits as its factorization.
12015425043133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16171501474.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 12015425043133 its reverse (33134052451021), we get a palindrome (45149477494154).
The spelling of 12015425043133 in words is "twelve trillion, fifteen billion, four hundred twenty-five million, forty-three thousand, one hundred thirty-three".
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