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1202110113014 = 24114659879427
BaseRepresentation
bin10001011111100011010…
…110001010010011110110
311020220212010020221212022
4101133203112022103312
5124143410142104024
62320124115353142
7152564260240016
oct21374326122366
94226763227768
101202110113014
114238a2902248
12174b882b27b2
13894878069a5
144227a887c46
152140a09e35e
hex117e358a4f6

1202110113014 has 8 divisors (see below), whose sum is σ = 1847144807928. Its totient is φ = 586395177040.

The previous prime is 1202110112993. The next prime is 1202110113077. The reversal of 1202110113014 is 4103110112021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×12021101130143 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1202110112983 and 1202110113001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7329939632 + ... + 7329939795.

It is an arithmetic number, because the mean of its divisors is an integer number (230893100991).

Almost surely, 21202110113014 is an apocalyptic number.

1202110113014 is a deficient number, since it is larger than the sum of its proper divisors (645034694914).

1202110113014 is a wasteful number, since it uses less digits than its factorization.

1202110113014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14659879470.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1202110113014 its reverse (4103110112021), we get a palindrome (5305220225035).

The spelling of 1202110113014 in words is "one trillion, two hundred two billion, one hundred ten million, one hundred thirteen thousand, fourteen".

Divisors: 1 2 41 82 14659879427 29319758854 601055056507 1202110113014