Base | Representation |
---|---|

bin | 10001011111101001111… |

… | …010001001111110001111 |

3 | 11020221010210102120102122 |

4 | 101133221322021332033 |

5 | 124144121333241421 |

6 | 2320143051243155 |

7 | 152600065123442 |

oct | 21375172117617 |

9 | 4227123376378 |

10 | 1202220212111 |

11 | 423949a71336 |

12 | 174bb91494bb |

13 | 894a4575199 |

14 | 4228b347659 |

15 | 21414a9b2ab |

hex | 117e9e89f8f |

1202220212111 has 2 divisors, whose sum is σ = 1202220212112. Its totient is φ = 1202220212110.

The previous prime is 1202220212071. The next prime is 1202220212129. The reversal of 1202220212111 is 1112120222021.

It is a strong prime.

It is an emirp because it is prime and its reverse (1112120222021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1202220212111 - 2^{18} = 1202219949967 is a prime.

It is a self number, because there is not a number *n* which added to its sum of digits gives 1202220212111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202220212131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601110106055 + 601110106056.

It is an arithmetic number, because the mean of its divisors is an integer number (601110106056).

Almost surely, 2^{1202220212111} is an apocalyptic number.

1202220212111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202220212111 is an equidigital number, since it uses as much as digits as its factorization.

1202220212111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 1202220212111 its reverse (1112120222021), we get a palindrome (2314340434132).

The spelling of 1202220212111 in words is "one trillion, two hundred two billion, two hundred twenty million, two hundred twelve thousand, one hundred eleven".

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