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12100433 = 12795279
BaseRepresentation
bin101110001010…
…001101010001
3211202202200012
4232022031101
511044203213
61111204305
7204565142
oct56121521
924682605
1012100433
116915264
124076695
132678927
14186dac9
1510e04a8
hexb8a351

12100433 has 4 divisors (see below), whose sum is σ = 12195840. Its totient is φ = 12005028.

The previous prime is 12100411. The next prime is 12100441. The reversal of 12100433 is 33400121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12100433 - 28 = 12100177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12103433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47513 + ... + 47766.

It is an arithmetic number, because the mean of its divisors is an integer number (3048960).

Almost surely, 212100433 is an apocalyptic number.

It is an amenable number.

12100433 is a deficient number, since it is larger than the sum of its proper divisors (95407).

12100433 is an equidigital number, since it uses as much as digits as its factorization.

12100433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95406.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 12100433 is about 3478.5676650024. The cubic root of 12100433 is about 229.5797809149.

Adding to 12100433 its reverse (33400121), we get a palindrome (45500554).

The spelling of 12100433 in words is "twelve million, one hundred thousand, four hundred thirty-three".

Divisors: 1 127 95279 12100433