Base | Representation |
---|---|
bin | 111000011001011101… |
… | …0001100110111001011 |
3 | 102120121120212010201201 |
4 | 1300302322030313023 |
5 | 3441014434431443 |
6 | 131345540125031 |
7 | 11515204142434 |
oct | 1606272146713 |
9 | 376546763651 |
10 | 121113202123 |
11 | 47400277381 |
12 | 1b580696777 |
13 | b561a0b254 |
14 | 5c0d12048b |
15 | 323ca9834d |
hex | 1c32e8cdcb |
121113202123 has 2 divisors, whose sum is σ = 121113202124. Its totient is φ = 121113202122.
The previous prime is 121113202117. The next prime is 121113202141. The reversal of 121113202123 is 321202311121.
It is a weak prime.
It is an emirp because it is prime and its reverse (321202311121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121113202123 - 213 = 121113193931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121113202123.
It is not a weakly prime, because it can be changed into another prime (121113202103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556601061 + 60556601062.
It is an arithmetic number, because the mean of its divisors is an integer number (60556601062).
Almost surely, 2121113202123 is an apocalyptic number.
121113202123 is a deficient number, since it is larger than the sum of its proper divisors (1).
121113202123 is an equidigital number, since it uses as much as digits as its factorization.
121113202123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 121113202123 its reverse (321202311121), we get a palindrome (442315513244).
The spelling of 121113202123 in words is "one hundred twenty-one billion, one hundred thirteen million, two hundred two thousand, one hundred twenty-three".
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