Base | Representation |
---|---|
bin | 101110001101… |
… | …010110010111 |
3 | 211210102022212 |
4 | 232031112113 |
5 | 11100111203 |
6 | 1111344035 |
7 | 204650516 |
oct | 56152627 |
9 | 24712285 |
10 | 12113303 |
11 | 69239a4 |
12 | 408201b |
13 | 2681747 |
14 | 187467d |
15 | 10e41d8 |
hex | b8d597 |
12113303 has 2 divisors, whose sum is σ = 12113304. Its totient is φ = 12113302.
The previous prime is 12113293. The next prime is 12113323. The reversal of 12113303 is 30331121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12113303 - 28 = 12113047 is a prime.
It is a Sophie Germain prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056651 + 6056652.
It is an arithmetic number, because the mean of its divisors is an integer number (6056652).
Almost surely, 212113303 is an apocalyptic number.
12113303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113303 is an equidigital number, since it uses as much as digits as its factorization.
12113303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
The square root of 12113303 is about 3480.4170727084. The cubic root of 12113303 is about 229.6611456303.
Adding to 12113303 its reverse (30331121), we get a palindrome (42444424).
The spelling of 12113303 in words is "twelve million, one hundred thirteen thousand, three hundred three".
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