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12121113 = 34040371
BaseRepresentation
bin101110001111…
…010000011001
3211210211001010
4232033100121
511100333423
61111444133
7205012344
oct56172031
924724033
1012121113
116929854
124086649
132685174
14187745b
1510e6693
hexb8f419

12121113 has 4 divisors (see below), whose sum is σ = 16161488. Its totient is φ = 8080740.

The previous prime is 12121103. The next prime is 12121121. The reversal of 12121113 is 31112121.

12121113 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12121113 - 24 = 12121097 is a prime.

It is a super-3 number, since 3×121211133 (a number of 22 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12121103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2020183 + ... + 2020188.

It is an arithmetic number, because the mean of its divisors is an integer number (4040372).

Almost surely, 212121113 is an apocalyptic number.

It is an amenable number.

12121113 is a deficient number, since it is larger than the sum of its proper divisors (4040375).

12121113 is an equidigital number, since it uses as much as digits as its factorization.

12121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4040374.

The product of its digits is 12, while the sum is 12.

The square root of 12121113 is about 3481.5388838845. The cubic root of 12121113 is about 229.7104927050.

Adding to 12121113 its reverse (31112121), we get a palindrome (43233234).

The spelling of 12121113 in words is "twelve million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 4040371 12121113