Base | Representation |
---|---|
bin | 10001101000111101010… |
… | …110111100001011000001 |
3 | 11021212221000100121021112 |
4 | 101220331112330023001 |
5 | 124330101302420111 |
6 | 2324514235333105 |
7 | 153402461462342 |
oct | 21507526741301 |
9 | 4255830317245 |
10 | 1212210201281 |
11 | 428106069032 |
12 | 176b268b1195 |
13 | 8a407168b91 |
14 | 429580220c9 |
15 | 217ebb2ce8b |
hex | 11a3d5bc2c1 |
1212210201281 has 2 divisors, whose sum is σ = 1212210201282. Its totient is φ = 1212210201280.
The previous prime is 1212210201277. The next prime is 1212210201313. The reversal of 1212210201281 is 1821020122121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 790470359056 + 421739842225 = 889084^2 + 649415^2 .
It is a cyclic number.
It is not a de Polignac number, because 1212210201281 - 22 = 1212210201277 is a prime.
It is a super-2 number, since 2×12122102012812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1212210204281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606105100640 + 606105100641.
It is an arithmetic number, because the mean of its divisors is an integer number (606105100641).
Almost surely, 21212210201281 is an apocalyptic number.
It is an amenable number.
1212210201281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212210201281 is an equidigital number, since it uses as much as digits as its factorization.
1212210201281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 256, while the sum is 23.
The spelling of 1212210201281 in words is "one trillion, two hundred twelve billion, two hundred ten million, two hundred one thousand, two hundred eighty-one".
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