Base | Representation |
---|---|
bin | 1011000010000100100101… |
… | …1101011111000110001011 |
3 | 1120221122012220012002212121 |
4 | 2300201021131133012023 |
5 | 3042220142322011334 |
6 | 41444313550552111 |
7 | 2361244106462431 |
oct | 260411135370613 |
9 | 46848186162777 |
10 | 12130220110219 |
11 | 3957441022002 |
12 | 143ab02208637 |
13 | 69cb4b070043 |
14 | 2dd16a3c2d51 |
15 | 160805261db4 |
hex | b084975f18b |
12130220110219 has 2 divisors, whose sum is σ = 12130220110220. Its totient is φ = 12130220110218.
The previous prime is 12130220110189. The next prime is 12130220110223. The reversal of 12130220110219 is 91201102203121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12130220110219 is a prime.
It is a super-2 number, since 2×121302201102192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12130220110193 and 12130220110202.
It is not a weakly prime, because it can be changed into another prime (12130220110289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065110055109 + 6065110055110.
It is an arithmetic number, because the mean of its divisors is an integer number (6065110055110).
Almost surely, 212130220110219 is an apocalyptic number.
12130220110219 is a deficient number, since it is larger than the sum of its proper divisors (1).
12130220110219 is an equidigital number, since it uses as much as digits as its factorization.
12130220110219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 12130220110219 in words is "twelve trillion, one hundred thirty billion, two hundred twenty million, one hundred ten thousand, two hundred nineteen".
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