12131113 has 2 divisors, whose sum is σ = 12131114. Its totient is φ = 12131112.

The previous prime is 12131099. The next prime is 12131159. The reversal of 12131113 is 31113121.

12131113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11471769 + 659344 = 3387^2 + 812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12131113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12131093 and 12131102.

It is not a weakly prime, because it can be changed into another prime (12131173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065556 + 6065557.

It is an arithmetic number, because the mean of its divisors is an integer number (6065557).

Almost surely, 2^12131113 is an apocalyptic number.

It is an amenable number.

12131113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12131113 is an equidigital number, since it uses as much as digits as its factorization.

12131113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18, while the sum is 13.

The square root of 12131113 is about 3482.9747343327. The cubic root of 12131113 is about 229.7736462429.

Adding to 12131113 its reverse (31113121), we get a palindrome (43244234).

It can be divided in two parts, 121 and 31113, that multiplied together give a palindrome (3764673).

The spelling of 12131113 in words is "twelve million, one hundred thirty-one thousand, one hundred thirteen".