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1213310103 = 3404436701
BaseRepresentation
bin100100001010001…
…1010010010010111
310010120001112120020
41020110122102113
54441101410403
6320221240223
742031652145
oct11024322227
93116045506
101213310103
11572977925
1229a403073
131644a4895
14b71d6595
15717b9453
hex4851a497

1213310103 has 4 divisors (see below), whose sum is σ = 1617746808. Its totient is φ = 808873400.

The previous prime is 1213310083. The next prime is 1213310141. The reversal of 1213310103 is 3010133121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213310103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213310143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202218348 + ... + 202218353.

It is an arithmetic number, because the mean of its divisors is an integer number (404436702).

Almost surely, 21213310103 is an apocalyptic number.

1213310103 is a deficient number, since it is larger than the sum of its proper divisors (404436705).

1213310103 is an equidigital number, since it uses as much as digits as its factorization.

1213310103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404436704.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 1213310103 is about 34832.6011517946. The cubic root of 1213310103 is about 1066.5730471328.

Adding to 1213310103 its reverse (3010133121), we get a palindrome (4223443224).

The spelling of 1213310103 in words is "one billion, two hundred thirteen million, three hundred ten thousand, one hundred three".

Divisors: 1 3 404436701 1213310103