Base | Representation |
---|---|
bin | 11011100101110000110000… |
… | …000011011001010100110000 |
3 | 120220122012111002201200010211 |
4 | 123211300300003121110300 |
5 | 111401032332343234440 |
6 | 1110023503005433504 |
7 | 34362454246046344 |
oct | 3345606003312460 |
9 | 526565432650124 |
10 | 121342222243120 |
11 | 35732a470865aa |
12 | 11738b2886b894 |
13 | 52926a3ac5408 |
14 | 21d6dcddb3624 |
15 | e065ca1c4eea |
hex | 6e5c300d9530 |
121342222243120 has 20 divisors (see below), whose sum is σ = 282120666715440. Its totient is φ = 48536888897216.
The previous prime is 121342222243097. The next prime is 121342222243133. The reversal of 121342222243120 is 21342222243121.
121342222243120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (20).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 758388888940 + ... + 758388889099.
It is an arithmetic number, because the mean of its divisors is an integer number (14106033335772).
Almost surely, 2121342222243120 is an apocalyptic number.
121342222243120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121342222243120 is an abundant number, since it is smaller than the sum of its proper divisors (160778444472320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121342222243120 is a wasteful number, since it uses less digits than its factorization.
121342222243120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1516777778052 (or 1516777778046 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 121342222243120 its reverse (21342222243121), we get a palindrome (142684444486241).
Subtracting from 121342222243120 its reverse (21342222243121), we obtain a palindrome (99999999999999).
The spelling of 121342222243120 in words is "one hundred twenty-one trillion, three hundred forty-two billion, two hundred twenty-two million, two hundred forty-three thousand, one hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •