Base | Representation |
---|---|
bin | 10110100111010010… |
… | …00000110101101011 |
3 | 1011100002211100222112 |
4 | 23103221000311223 |
5 | 144331003203012 |
6 | 5324412512535 |
7 | 606600031106 |
oct | 132351006553 |
9 | 34302740875 |
10 | 12140678507 |
11 | 5170107501 |
12 | 2429a7b74b |
13 | 11b634b949 |
14 | 83259b73d |
15 | 4b0cad122 |
hex | 2d3a40d6b |
12140678507 has 2 divisors, whose sum is σ = 12140678508. Its totient is φ = 12140678506.
The previous prime is 12140678491. The next prime is 12140678509. The reversal of 12140678507 is 70587604121.
12140678507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12140678507 - 24 = 12140678491 is a prime.
It is a super-2 number, since 2×121406785072 (a number of 21 digits) contains 22 as substring.
Together with 12140678509, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12140678509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070339253 + 6070339254.
It is an arithmetic number, because the mean of its divisors is an integer number (6070339254).
Almost surely, 212140678507 is an apocalyptic number.
12140678507 is a deficient number, since it is larger than the sum of its proper divisors (1).
12140678507 is an equidigital number, since it uses as much as digits as its factorization.
12140678507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 94080, while the sum is 41.
The spelling of 12140678507 in words is "twelve billion, one hundred forty million, six hundred seventy-eight thousand, five hundred seven".
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