Base | Representation |
---|---|
bin | 1011000110001000100101… |
… | …0100101001100000001111 |
3 | 1121012022100202002021001211 |
4 | 2301202021110221200033 |
5 | 3044341110304341421 |
6 | 41540335132115251 |
7 | 2366264434402546 |
oct | 261421124514017 |
9 | 47168322067054 |
10 | 12200011012111 |
11 | 3983aa518761a |
12 | 145053b005b27 |
13 | 6a65c10961b0 |
14 | 3026ab32915d |
15 | 16253c31c9e1 |
hex | b188952980f |
12200011012111 has 4 divisors (see below), whose sum is σ = 13138473397672. Its totient is φ = 11261548626552.
The previous prime is 12200011012051. The next prime is 12200011012169. The reversal of 12200011012111 is 11121011000221.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12200011012111 - 213 = 12200011003919 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 938462385547 = 12200011012111 / (1 + 2 + 2 + 0 + 0 + 0 + 1 + 1 + 0 + 1 + 2 + 1 + 1 + 1).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12200011012091 and 12200011012100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12200011012181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469231192761 + ... + 469231192786.
It is an arithmetic number, because the mean of its divisors is an integer number (3284618349418).
Almost surely, 212200011012111 is an apocalyptic number.
12200011012111 is a deficient number, since it is larger than the sum of its proper divisors (938462385561).
12200011012111 is an equidigital number, since it uses as much as digits as its factorization.
12200011012111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 938462385560.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 12200011012111 its reverse (11121011000221), we get a palindrome (23321022012332).
The spelling of 12200011012111 in words is "twelve trillion, two hundred billion, eleven million, twelve thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.134 sec. • engine limits •