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12212031113 is a prime number
BaseRepresentation
bin10110101111110010…
…01100111010001001
31011112002002110100122
423113321030322021
5200002234443423
65335442113025
7611424360152
oct132771147211
934462073318
1012212031113
1151a74117a7
12244994b775
1311c8072019
1483bc52929
154b71a48c8
hex2d7e4ce89

12212031113 has 2 divisors, whose sum is σ = 12212031114. Its totient is φ = 12212031112.

The previous prime is 12212031077. The next prime is 12212031119. The reversal of 12212031113 is 31113021221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10983668809 + 1228362304 = 104803^2 + 35048^2 .

It is an emirp because it is prime and its reverse (31113021221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12212031113 - 212 = 12212027017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12212031091 and 12212031100.

It is not a weakly prime, because it can be changed into another prime (12212031119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106015556 + 6106015557.

It is an arithmetic number, because the mean of its divisors is an integer number (6106015557).

Almost surely, 212212031113 is an apocalyptic number.

It is an amenable number.

12212031113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12212031113 is an equidigital number, since it uses as much as digits as its factorization.

12212031113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12212031113 its reverse (31113021221), we get a palindrome (43325052334).

The spelling of 12212031113 in words is "twelve billion, two hundred twelve million, thirty-one thousand, one hundred thirteen".