Base | Representation |
---|---|
bin | 11011110001001000001101… |
… | …001011000101001111001011 |
3 | 121000101212122020001000200011 |
4 | 123301020031023011033023 |
5 | 112001332030200301212 |
6 | 1111422402413052351 |
7 | 34503055512602446 |
oct | 3361101513051713 |
9 | 530355566030604 |
10 | 122123321103307 |
11 | 35a04234018197 |
12 | 118443991870b7 |
13 | 531b244c39094 |
14 | 2222b2bd7665d |
15 | e1ba93e594a7 |
hex | 6f120d2c53cb |
122123321103307 has 2 divisors, whose sum is σ = 122123321103308. Its totient is φ = 122123321103306.
The previous prime is 122123321103281. The next prime is 122123321103331. The reversal of 122123321103307 is 703301123321221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122123321103307 - 215 = 122123321070539 is a prime.
It is not a weakly prime, because it can be changed into another prime (122123331103307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61061660551653 + 61061660551654.
It is an arithmetic number, because the mean of its divisors is an integer number (61061660551654).
Almost surely, 2122123321103307 is an apocalyptic number.
122123321103307 is a deficient number, since it is larger than the sum of its proper divisors (1).
122123321103307 is an equidigital number, since it uses as much as digits as its factorization.
122123321103307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 122123321103307 its reverse (703301123321221), we get a palindrome (825424444424528).
The spelling of 122123321103307 in words is "one hundred twenty-two trillion, one hundred twenty-three billion, three hundred twenty-one million, one hundred three thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •