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123123331212113 is a prime number
BaseRepresentation
bin11011111111101011100010…
…011010111010001101010001
3121010221110211122111000211102
4123333223202122322031101
5112114223040242241423
61113510024424154145
734635236632353311
oct3377534232721521
9533843748430742
10123123331212113
113625a347717a71
1211986162608955
135391632333b5b
1422592b5891441
15e37ac151ac28
hex6ffae26ba351

123123331212113 has 2 divisors, whose sum is σ = 123123331212114. Its totient is φ = 123123331212112.

The previous prime is 123123331212073. The next prime is 123123331212137. The reversal of 123123331212113 is 311212133321321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72166248285184 + 50957082926929 = 8495072^2 + 7138423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123123331212113 is a prime.

It is not a weakly prime, because it can be changed into another prime (123123331212313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61561665606056 + 61561665606057.

It is an arithmetic number, because the mean of its divisors is an integer number (61561665606057).

Almost surely, 2123123331212113 is an apocalyptic number.

It is an amenable number.

123123331212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

123123331212113 is an equidigital number, since it uses as much as digits as its factorization.

123123331212113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 29.

Adding to 123123331212113 its reverse (311212133321321), we get a palindrome (434335464533434).

The spelling of 123123331212113 in words is "one hundred twenty-three trillion, one hundred twenty-three billion, three hundred thirty-one million, two hundred twelve thousand, one hundred thirteen".