Base | Representation |
---|---|
bin | 1011001101001010000001… |
… | …0110011010001101010001 |
3 | 1121121211202201201200221201 |
4 | 2303102200112122031101 |
5 | 3103330201021342001 |
6 | 42112010442151201 |
7 | 2411065231513456 |
oct | 263224026321521 |
9 | 47554681650851 |
10 | 12320656434001 |
11 | 3a201853a3763 |
12 | 146b9aaab2501 |
13 | 6b4aa9bc07b6 |
14 | 30847427d82d |
15 | 16574dcb4501 |
hex | b34a059a351 |
12320656434001 has 2 divisors, whose sum is σ = 12320656434002. Its totient is φ = 12320656434000.
The previous prime is 12320656433951. The next prime is 12320656434007. The reversal of 12320656434001 is 10043465602321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7767229650625 + 4553426783376 = 2786975^2 + 2133876^2 .
It is an emirp because it is prime and its reverse (10043465602321) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12320656434001 is a prime.
It is not a weakly prime, because it can be changed into another prime (12320656434007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160328217000 + 6160328217001.
It is an arithmetic number, because the mean of its divisors is an integer number (6160328217001).
Almost surely, 212320656434001 is an apocalyptic number.
It is an amenable number.
12320656434001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320656434001 is an equidigital number, since it uses as much as digits as its factorization.
12320656434001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 37.
The spelling of 12320656434001 in words is "twelve trillion, three hundred twenty billion, six hundred fifty-six million, four hundred thirty-four thousand, one".
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