Base | Representation |
---|---|
bin | 111001011010111101… |
… | …1110100000110001111 |
3 | 102210021210020012120102 |
4 | 1302311323310012033 |
5 | 4010020212042041 |
6 | 132352024041315 |
7 | 11623525643135 |
oct | 1626573640617 |
9 | 383253205512 |
10 | 123311440271 |
11 | 48329103218 |
12 | 1ba9490323b |
13 | b822273996 |
14 | 5d7b05d755 |
15 | 331aa6809b |
hex | 1cb5ef418f |
123311440271 has 2 divisors, whose sum is σ = 123311440272. Its totient is φ = 123311440270.
The previous prime is 123311440177. The next prime is 123311440277. The reversal of 123311440271 is 172044113321.
It is a strong prime.
It is an emirp because it is prime and its reverse (172044113321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123311440271 - 218 = 123311178127 is a prime.
It is a super-2 number, since 2×1233114402712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123311440277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61655720135 + 61655720136.
It is an arithmetic number, because the mean of its divisors is an integer number (61655720136).
Almost surely, 2123311440271 is an apocalyptic number.
123311440271 is a deficient number, since it is larger than the sum of its proper divisors (1).
123311440271 is an equidigital number, since it uses as much as digits as its factorization.
123311440271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 123311440271 its reverse (172044113321), we get a palindrome (295355553592).
The spelling of 123311440271 in words is "one hundred twenty-three billion, three hundred eleven million, four hundred forty thousand, two hundred seventy-one".
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