Base | Representation |
---|---|
bin | 111001101111111010… |
… | …1011011111000110101 |
3 | 102212002202222211120002 |
4 | 1303133311123320311 |
5 | 4012440142130232 |
6 | 132545455121045 |
7 | 11650123050326 |
oct | 1633765337065 |
9 | 385082884502 |
10 | 124014411317 |
11 | 486599a1825 |
12 | 20050213185 |
13 | b904ab3494 |
14 | 600656c44d |
15 | 335c625b62 |
hex | 1cdfd5be35 |
124014411317 has 2 divisors, whose sum is σ = 124014411318. Its totient is φ = 124014411316.
The previous prime is 124014411289. The next prime is 124014411347. The reversal of 124014411317 is 713114410421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120704825476 + 3309585841 = 347426^2 + 57529^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124014411317 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 124014411317.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124014411347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62007205658 + 62007205659.
It is an arithmetic number, because the mean of its divisors is an integer number (62007205659).
Almost surely, 2124014411317 is an apocalyptic number.
It is an amenable number.
124014411317 is a deficient number, since it is larger than the sum of its proper divisors (1).
124014411317 is an equidigital number, since it uses as much as digits as its factorization.
124014411317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 124014411317 its reverse (713114410421), we get a palindrome (837128821738).
The spelling of 124014411317 in words is "one hundred twenty-four billion, fourteen million, four hundred eleven thousand, three hundred seventeen".
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