Base | Representation |
---|---|

bin | 1011011000010111100010… |

… | …1001000010010010000011 |

3 | 1122022020220212101110021201 |

4 | 2312011320221002102003 |

5 | 3120004131010201134 |

6 | 42340303005402031 |

7 | 2431024224654556 |

oct | 266057051022203 |

9 | 48266825343251 |

10 | 12513263756419 |

11 | 3a94933196868 |

12 | 14a11a2869317 |

13 | 6c9cc375a32a |

14 | 3139065c869d |

15 | 16a773205914 |

hex | b6178a42483 |

12513263756419 has 2 divisors, whose sum is σ = 12513263756420. Its totient is φ = 12513263756418.

The previous prime is 12513263756359. The next prime is 12513263756423. The reversal of 12513263756419 is 91465736231521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12513263756419 - 2^{7} = 12513263756291 is a prime.

It is a super-2 number, since 2×12513263756419^{2} (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number *n* which added to its sum of digits gives 12513263756419.

It is not a weakly prime, because it can be changed into another prime (12513263750419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256631878209 + 6256631878210.

It is an arithmetic number, because the mean of its divisors is an integer number (6256631878210).

Almost surely, 2^{12513263756419} is an apocalyptic number.

12513263756419 is a deficient number, since it is larger than the sum of its proper divisors (1).

12513263756419 is an equidigital number, since it uses as much as digits as its factorization.

12513263756419 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8164800, while the sum is 55.

The spelling of 12513263756419 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, four hundred nineteen".

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