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1252513394129 is a prime number
BaseRepresentation
bin10010001110011111100…
…111011010110111010001
311102201221210220221011202
4102032133213122313101
5131010121412103004
62355221404520545
7156330310121324
oct22163747326721
94381853827152
101252513394129
11443208181378
121828b4250155
139115ac9659a
144489c9947bb
15228aa054b1e
hex1239f9dadd1

1252513394129 has 2 divisors, whose sum is σ = 1252513394130. Its totient is φ = 1252513394128.

The previous prime is 1252513394087. The next prime is 1252513394137. The reversal of 1252513394129 is 9214933152521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 841343893504 + 411169500625 = 917248^2 + 641225^2 .

It is a cyclic number.

It is not a de Polignac number, because 1252513394129 - 236 = 1183793917393 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1252513394929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626256697064 + 626256697065.

It is an arithmetic number, because the mean of its divisors is an integer number (626256697065).

Almost surely, 21252513394129 is an apocalyptic number.

It is an amenable number.

1252513394129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252513394129 is an equidigital number, since it uses as much as digits as its factorization.

1252513394129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 583200, while the sum is 47.

The spelling of 1252513394129 in words is "one trillion, two hundred fifty-two billion, five hundred thirteen million, three hundred ninety-four thousand, one hundred twenty-nine".