Base | Representation |
---|---|
bin | 10010001110011111100… |
… | …111011100110110011011 |
3 | 11102201221210221100100011 |
4 | 102032133213130312123 |
5 | 131010121412333032 |
6 | 2355221405022351 |
7 | 156330310154131 |
oct | 22163747346633 |
9 | 4381853840304 |
10 | 1252513402267 |
11 | 4432081874a6 |
12 | 1828b42549b7 |
13 | 9115ac9a1ba |
14 | 4489c997751 |
15 | 228aa057247 |
hex | 1239f9dcd9b |
1252513402267 has 2 divisors, whose sum is σ = 1252513402268. Its totient is φ = 1252513402266.
The previous prime is 1252513402249. The next prime is 1252513402339. The reversal of 1252513402267 is 7622043152521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1252513402267 - 211 = 1252513400219 is a prime.
It is not a weakly prime, because it can be changed into another prime (1252513402237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626256701133 + 626256701134.
It is an arithmetic number, because the mean of its divisors is an integer number (626256701134).
Almost surely, 21252513402267 is an apocalyptic number.
1252513402267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252513402267 is an equidigital number, since it uses as much as digits as its factorization.
1252513402267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 40.
Adding to 1252513402267 its reverse (7622043152521), we get a palindrome (8874556554788).
The spelling of 1252513402267 in words is "one trillion, two hundred fifty-two billion, five hundred thirteen million, four hundred two thousand, two hundred sixty-seven".
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