Base | Representation |
---|---|
bin | 10010001110011111100… |
… | …111011100110111010001 |
3 | 11102201221210221100102011 |
4 | 102032133213130313101 |
5 | 131010121412333241 |
6 | 2355221405022521 |
7 | 156330310154236 |
oct | 22163747346721 |
9 | 4381853840364 |
10 | 1252513402321 |
11 | 443208187545 |
12 | 1828b4254a41 |
13 | 9115ac9a22c |
14 | 4489c99778d |
15 | 228aa057281 |
hex | 1239f9dcdd1 |
1252513402321 has 4 divisors (see below), whose sum is σ = 1252593363952. Its totient is φ = 1252433440692.
The previous prime is 1252513402267. The next prime is 1252513402339. The reversal of 1252513402321 is 1232043152521.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1252513402321 - 213 = 1252513394129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1252513402121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39957315 + ... + 39988648.
It is an arithmetic number, because the mean of its divisors is an integer number (313148340988).
Almost surely, 21252513402321 is an apocalyptic number.
It is an amenable number.
1252513402321 is a deficient number, since it is larger than the sum of its proper divisors (79961631).
1252513402321 is an equidigital number, since it uses as much as digits as its factorization.
1252513402321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79961630.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1252513402321 its reverse (1232043152521), we get a palindrome (2484556554842).
The spelling of 1252513402321 in words is "one trillion, two hundred fifty-two billion, five hundred thirteen million, four hundred two thousand, three hundred twenty-one".
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