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BaseRepresentation
bin10011100101
31201102
4103211
520003
65445
73440
oct2345
91642
101253
11a3a
12885
13755
14657
15588
hex4e5

1253 has 4 divisors (see below), whose sum is σ = 1440. Its totient is φ = 1068.

The previous prime is 1249. The next prime is 1259. The reversal of 1253 is 3521.

1253 is nontrivially palindromic in base 6 and base 11.

1253 is an esthetic number in base 8, because in such base its adjacent digits differ by 1.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3521 = 7503.

It is a cyclic number.

It is not a de Polignac number, because 1253 - 22 = 1249 is a prime.

It is a Duffinian number.

1253 is an undulating number in base 11.

It is a plaindrome in base 8 and base 15.

It is a nialpdrome in base 12 and base 13.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83 + ... + 96.

It is an arithmetic number, because the mean of its divisors is an integer number (360).

It is an amenable number.

1253 is a deficient number, since it is larger than the sum of its proper divisors (187).

1253 is an equidigital number, since it uses as much as digits as its factorization.

1253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186.

The product of its digits is 30, while the sum is 11.

The square root of 1253 is about 35.3977400409. The cubic root of 1253 is about 10.7807843039.

Adding to 1253 its reverse (3521), we get a palindrome (4774).

It can be divided in two parts, 125 and 3, that added together give a 7-th power (128 = 27).

The spelling of 1253 in words is "one thousand, two hundred fifty-three".

Divisors: 1 7 179 1253