Base | Representation |
---|---|
bin | 1011011001100110110110… |
… | …0101000011100010101001 |
3 | 1122101021212112212002101121 |
4 | 2312121231211003202221 |
5 | 3120331231032000410 |
6 | 42354143312015241 |
7 | 2432406623362453 |
oct | 266315545034251 |
9 | 48337775762347 |
10 | 12534553000105 |
11 | 3aa2968436734 |
12 | 14a5344531521 |
13 | 6cc007275046 |
14 | 314965bd12d3 |
15 | 16b0bc2399da |
hex | b666d9438a9 |
12534553000105 has 16 divisors (see below), whose sum is σ = 16764479556480. Its totient is φ = 8941055761152.
The previous prime is 12534553000097. The next prime is 12534553000127. The reversal of 12534553000105 is 50100035543521.
12534553000105 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12534553000105 - 23 = 12534553000097 is a prime.
It is a super-2 number, since 2×125345530001052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3880664949 + ... + 3880668178.
It is an arithmetic number, because the mean of its divisors is an integer number (1047779972280).
Almost surely, 212534553000105 is an apocalyptic number.
It is an amenable number.
12534553000105 is a deficient number, since it is larger than the sum of its proper divisors (4229926556375).
12534553000105 is a wasteful number, since it uses less digits than its factorization.
12534553000105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7761333168.
The product of its (nonzero) digits is 45000, while the sum is 34.
Adding to 12534553000105 its reverse (50100035543521), we get a palindrome (62634588543626).
The spelling of 12534553000105 in words is "twelve trillion, five hundred thirty-four billion, five hundred fifty-three million, one hundred five", and thus it is an aban number.
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