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125403 = 341801
BaseRepresentation
bin11110100111011011
320101000120
4132213123
513003103
62404323
71031415
oct364733
9211016
10125403
1186243
12606a3
1345105
14339b5
1527253
hex1e9db

125403 has 4 divisors (see below), whose sum is σ = 167208. Its totient is φ = 83600.

The previous prime is 125399. The next prime is 125407. The reversal of 125403 is 304521.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (125399) and next prime (125407).

It is a cyclic number.

It is not a de Polignac number, because 125403 - 22 = 125399 is a prime.

It is a D-number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 125403.

It is not an unprimeable number, because it can be changed into a prime (125407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20898 + ... + 20903.

It is an arithmetic number, because the mean of its divisors is an integer number (41802).

2125403 is an apocalyptic number.

125403 is a deficient number, since it is larger than the sum of its proper divisors (41805).

125403 is an equidigital number, since it uses as much as digits as its factorization.

125403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41804.

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 125403 is about 354.1228600359. The cubic root of 125403 is about 50.0536756911.

Adding to 125403 its reverse (304521), we get a palindrome (429924).

It can be divided in two parts, 125 and 403, that added together give a triangular number (528 = T32).

The spelling of 125403 in words is "one hundred twenty-five thousand, four hundred three".

Divisors: 1 3 41801 125403