Base | Representation |
---|---|
bin | 1110111111100… |
… | …00100001101111 |
3 | 22202122120011111 |
4 | 13133300201233 |
5 | 224144000433 |
6 | 20251332451 |
7 | 3054663655 |
oct | 737604157 |
9 | 282576144 |
10 | 125765743 |
11 | 64a9a734 |
12 | 36151127 |
13 | 200953cc |
14 | 129badd5 |
15 | b093dcd |
hex | 77f086f |
125765743 has 2 divisors, whose sum is σ = 125765744. Its totient is φ = 125765742.
The previous prime is 125765741. The next prime is 125765789. The reversal of 125765743 is 347567521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125765743 - 21 = 125765741 is a prime.
It is a super-2 number, since 2×1257657432 = 31634044224684098, which contains 22 as substring.
Together with 125765741, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 125765696 and 125765705.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125765741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62882871 + 62882872.
It is an arithmetic number, because the mean of its divisors is an integer number (62882872).
Almost surely, 2125765743 is an apocalyptic number.
125765743 is a deficient number, since it is larger than the sum of its proper divisors (1).
125765743 is an equidigital number, since it uses as much as digits as its factorization.
125765743 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 176400, while the sum is 40.
The square root of 125765743 is about 11214.5326697103. The cubic root of 125765743 is about 501.0189128893.
The spelling of 125765743 in words is "one hundred twenty-five million, seven hundred sixty-five thousand, seven hundred forty-three".
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