Base | Representation |
---|---|
bin | 1011011111101011011110… |
… | …1010011000010101010101 |
3 | 1122202021010221100010110222 |
4 | 2313322313222120111111 |
5 | 3124033404013000302 |
6 | 42514115153124125 |
7 | 2443062051663425 |
oct | 267726752302525 |
9 | 48667127303428 |
10 | 12638875125077 |
11 | 4033131571243 |
12 | 15015b9859645 |
13 | 708ac134c686 |
14 | 319a20c98485 |
15 | 16db75b28da2 |
hex | b7eb7a98555 |
12638875125077 has 2 divisors, whose sum is σ = 12638875125078. Its totient is φ = 12638875125076.
The previous prime is 12638875125011. The next prime is 12638875125127. The reversal of 12638875125077 is 77052157883621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6560288425636 + 6078586699441 = 2561306^2 + 2465479^2 .
It is a cyclic number.
It is not a de Polignac number, because 12638875125077 - 212 = 12638875120981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12638875122077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6319437562538 + 6319437562539.
It is an arithmetic number, because the mean of its divisors is an integer number (6319437562539).
Almost surely, 212638875125077 is an apocalyptic number.
It is an amenable number.
12638875125077 is a deficient number, since it is larger than the sum of its proper divisors (1).
12638875125077 is an equidigital number, since it uses as much as digits as its factorization.
12638875125077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39513600, while the sum is 62.
The spelling of 12638875125077 in words is "twelve trillion, six hundred thirty-eight billion, eight hundred seventy-five million, one hundred twenty-five thousand, seventy-seven".
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