Base | Representation |
---|---|
bin | 1011100010100111011110… |
… | …0101110101100000011111 |
3 | 1122221002101220112012200201 |
4 | 2320221313211311200133 |
5 | 3130400231442041313 |
6 | 42553222514204331 |
7 | 2446526445434356 |
oct | 270516745654037 |
9 | 48832356465621 |
10 | 12689339799583 |
11 | 4052578563107 |
12 | 150b3422836a7 |
13 | 7107a4456515 |
14 | 31c24b1c699d |
15 | 17012b1aa0dd |
hex | b8a7797581f |
12689339799583 has 2 divisors, whose sum is σ = 12689339799584. Its totient is φ = 12689339799582.
The previous prime is 12689339799559. The next prime is 12689339799641. The reversal of 12689339799583 is 38599793398621.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12689339799583 is a prime.
It is a super-2 number, since 2×126893397995832 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12689339799497 and 12689339799506.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12689339790583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6344669899791 + 6344669899792.
It is an arithmetic number, because the mean of its divisors is an integer number (6344669899792).
Almost surely, 212689339799583 is an apocalyptic number.
12689339799583 is a deficient number, since it is larger than the sum of its proper divisors (1).
12689339799583 is an equidigital number, since it uses as much as digits as its factorization.
12689339799583 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4761711360, while the sum is 82.
The spelling of 12689339799583 in words is "twelve trillion, six hundred eighty-nine billion, three hundred thirty-nine million, seven hundred ninety-nine thousand, five hundred eighty-three".
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